Question bank/JEE Main/Mathematics

If minimum distance between
$y^{2} = 4x\ and\ x^{2} + y^{2} - 4x - 16y + 63 = 0\ is\ \sqrt{p}$ then
value of $\frac{1111}{100}p$ is
U;qure nwjh $\sqrt{p}$gS rc $\frac{1111}{100}p$dk eku

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[IMAGE] Minimum distance along common norma
$y = mx - 2am - am^{3}$
it passes through centre of circle B(2,8);g o`Ùk B(2,8) Unz ls xqtjrh
$\Rightarrow m^{3} = - 8$
m = -2
⇒ Point of contact A[IMAGE] (4,4)
$\Rightarrow \ minimum\ distance\ = |AB - r| = \sqrt{5}$
⇒ U;wure nwjh = |AB -r| = [IMAGE]

Source: Grass-G / M-26 Mathematics Paper 1 15 Jan.docx