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JEE MainMathematicsModerateCircles

If circles x2+y2=c x^{2} + y^{2} = c\ with radius
3 and x2+y2+ax+by+c=0\sqrt{3}\ and\ x^{2} + y^{2} + ax + by + c = 0with radius
[IMAGE] intersect at two points A and B. If length of AB

is
l\sqrt{\mathcal{l}}then l2\mathcal{l}^{2}is;fn3 \sqrt{3}\ f= o`Ùk x2+y2=c x^{2} + y^{2} = c\ gS rFkk
o`Ùk
 x2+y2+ax+by+c=0\ x^{2} + y^{2} + ax + by + c = 0dh
f= nks fcUnqvksa A rFkk B ij izfrPNsn djrh AB


Show answer and solution
c =3
a24+b24−c=6\frac{a^{2}}{4} + \frac{b^{2}}{4} - c = 6
a2+b2=36a^{2} + b^{2} = 36
[IMAGE] common chord (AB) = ax + by + 2c =0

mHk;fu"B thok (AB) = ax + by + 2c =0

AB = 2AM

=23−1=22= 2\sqrt{3 - 1} = 2\sqrt{2}

Source: Grass-G / M-26 Mathematics Paper 1 15 Jan.docx

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