Question bank/JEE Main/Mathematics
JEE MainMathematicsModerateCircles
Equation of the circle which circumscribes the square formed by
the lines xy-9x-2y+18 = 0 and xy - 5x - 6y + 30 = 0 is
Show answer and solution
Given equations represent the lines x=2, y=9, x=6, y=5 which
forms a square of each side equal to 4 vertex A(2,5), C (6,9). Centre of
the circle is the mid point of AC and the radius is (1/2) AC. Hence the
equation of the circle is
lehdj.k x=2, y=9, x=6, y=5 tks fd oxZ dh çR;sd
Hkqtk 4 ds cjkcj gSA 'kh"kZ A(2,5), C (6,9), o`Ùk
forms a square of each side equal to 4 vertex A(2,5), C (6,9). Centre of
the circle is the mid point of AC and the radius is (1/2) AC. Hence the
equation of the circle is
lehdj.k x=2, y=9, x=6, y=5 tks fd oxZ dh çR;sd
Hkqtk 4 ds cjkcj gSA 'kh"kZ A(2,5), C (6,9), o`Ùk
Source: Grass-G / M-26 Mathematics Paper 1 15 Jan.docx
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