Question bank/JEE Main/Mathematics

All the vertices of a trapezium lie on the parabola y^2 = 4x.
Its diagonals pass through (1, 0) and have a length $\frac{25}{4}$ units
each. Then the area of the trapezium is,d leyEc prqHkqZt ds pkjksa y^2 = 4x ij fLFkr gSA blds
fod.kZ (1, 0) xqtjrs gS rFkk nksuks dh yEckbZ $\frac{25}{4}$ bdkbZ gS]
rc leyEc prqHkqZt

A100 sq. units oxZ bdkbZB75/4 sq. unit oxZ bdkbZC25/4 sq. units oxZ bdkbZD65 sq. units oxZ bdkbZ

Show answer and solution▾

Also, $AS = 1 + t^{2}\& CS = 25/4 - \left( 1 + t^{2} \right)$
$\Rightarrow t = \pm 2, \pm 1/2$

Source: Grass-G / M-27 Mathematics Paper 2 15 Jan.docx