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JEE MainMathematicsEasyCircles

Equation of circle touching the line x+y=4x + y = 4at (1, 3) and
intersecting the circle
x2+y2=4x^{2} + y^{2} = 4orthogonally, is
gksxk tks o`Ùk
x2+y2=4x^{2} + y^{2} = 4dks yfEcd izfrPNsn djrk

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Circle
⇒x2+y2+x(λ+2)+y(λ−6)+(10−4λ)=0\Rightarrow x^{2} + y^{2} + x(\lambda + 2) + y(\lambda - 6) + (10 - 4\lambda) = 0
2g1g2+2f1f2=4+λ22g_{1}g_{2} + 2f_{1}f_{2} = 4 + \lambda_{2}
⇒0+0=10−4λ−4⇒λ=32\Rightarrow 0 + 0 = 10 - 4\lambda - 4 \Rightarrow \lambda = \frac{3}{2}
⇒x2+y2−x2−9y2+4=0\Rightarrow x^{2} + y^{2} - \frac{x}{2} - \frac{9y}{2} + 4 = 0

Source: Grass-G / M-27 Mathematics Paper 2 15 Jan.docx

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