Question bank/JEE Main/Mathematics

Area of the region bounded by points (x,y) satisfying x^2 + y^2
≤ |x| + |y| is
x^2 + y^2 ≤ |x| + |y|

A2π + 4B$\frac{\pi}{2} + 1$CπDπ + 2

Show answer and solution▾

[IMAGE] Required area = 4[A(ΔOPB) + A(semi PCB)]
A(ΔOAB) = $\frac{1}{2}$
A(semi PCB) = $\frac{\pi}{4}$
Hence = 4 $\left( \frac{1}{2} + \frac{\pi}{4} \right)$
= π + 2

Source: Grass-G / M-27 Mathematics Paper 2 15 Jan.docx