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JEE MainMathematicsToughThoery of equation

If
α=e(2πi7) and f(x)=A0+∑k=120\mspace2muAkxk\alpha = e^{\left( \frac{2\pi i}{7} \right)}\ and\ f(x) = A_{0} + \sum_{k = 1}^{20}\mspace{2mu} A_{k}x^{k}
and the value of

f(x)+f(αx)+f(α2x)+…+              f(α6x) is k(A0+A7x7+ A14x14f(x) + f(\alpha x) + f\left( \alpha^{2}x \right) + \ldots + \ \ \ \ \ \ \ \ \ \ \ \ \ \ f\left( \alpha^{6}x \right)\ is\ k\left( A_{0} + A_{7}x^{7} + \right.\ A_{14}x^{14})
then the value of k is

Show answer and solution
$\ We\ know\ 1 + a^{r} + a^{2r} + \ldots\ldots.. + a^{6r} = \left\{ \begin{matrix}
7:r = \ multipleof\ 7 \\

0::r \neq \ multipleof\ 7

\end{matrix} \right.\ $

f(x)=A0+∑k=120\mspace2muAkxkf(x) = A_{0} + \sum_{k = 1}^{20}\mspace{2mu} A_{k}x^{k}
f(αx)=A0+∑k=120\mspace2muAkαkxkf(\alpha x) = A_{0} + \sum_{k = 1}^{20}\mspace{2mu} A_{k}\alpha^{k}x^{k}
add

f(x)+f(αx)+…..+f(α6x)=7A0+A1(1+α+……..+α6)x+…………+A7(7)x7+                ……..+A14(7)x14+……..f(x) + f(\alpha x) + \ldots.. + f\left( \alpha^{6}x \right) = 7A_{0} + A_{1}\left( 1 + \alpha + \ldots\ldots.. + \alpha^{6} \right)x + \ldots\ldots\ldots\ldots + A_{7}(7)x^{7} + \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ldots\ldots.. + A_{14}(7)x^{14} + \ldots\ldots..
=7A0+A1(0)+A2(0)+……+A6(0)+A7(7)x7+……+A14(7)x14+……+A20(0)= 7A_{0} + A_{1}(0) + A_{2}(0) + \ldots\ldots + A_{6}(0) + A_{7}(7)x^{7} + \ldots\ldots + A_{14}(7)x^{14} + \ldots\ldots + A_{20}(0)
=7(A0+A7X7+A14X14)⇒k=7\begin{matrix} = 7\left( A_{0} + A_{7}X^{7} + A_{14}X^{14} \right) \\ \Rightarrow k = 7 \end{matrix}

Source: Grass-G / M-28 Mathematics Paper FST 16 Jan.docx

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