JEE MainMathematicsModeratePermutations and Combinations

The number of ways in which 7 identical balls can be distributed
into 3 different boxes such that no box remains empty is n and p is the
least even prime number, then
$\left\lbrack \frac{n - p}{3} \right\rbrack$ is equal to where
denotesG.I.F.

Show answer and solution

n = \ ^{7 - 1}C_{4} = \ ^{6}C_{2} = \frac{6.5}{2} = 15

New p =2

\left\lbrack \frac{n - p}{3} \right\rbrack = \left\lbrack \frac{13}{3} \right\rbrack

Source: Grass-G / M-28 Mathematics Paper FST 16 Jan.docx

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