Question bank/JEE Main/Mathematics

JEE MainMathematicsModerateProbability

For an initial screening of an admission test, a candidate is
given fifty problems to solve. If the probability that the candidate can

solve any problem is [IMAGE],then the probability that he

is unable to solve less than two problems is

Show answer and solution
There are 50 questions in an exam.
Probability of each question to be correct =
=p=45= p = \frac{4}{5}
probability of each question is incorrect
=q=15= q = \frac{1}{5}
Let X= number of correct question in 50 questions.

Hence required probability

=(45)50+ 50C1(15)(45)49= \left( \frac{4}{5} \right)^{50} + \ ^{50}C_{1}\left( \frac{1}{5} \right)\left( \frac{4}{5} \right)^{49}
=(45)49(45+10)(45)=545(45)49= \left( \frac{4}{5} \right)^{49}\left( \frac{4}{5} + 10 \right)\left( \frac{4}{5} \right) = \frac{54}{5}\left( \frac{4}{5} \right)^{49}

Source: Grass-G / M-28 Mathematics Paper FST 16 Jan.docx

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