Question bank/JEE Main/Mathematics

A triangle has a vertex at (1,2) and the mid points of the two
sides through it are (-1,1) and (2,3). Then the centroid of this
triangle is

A$\left( 1,\frac{7}{3} \right)$B$\left( \frac{1}{3},\frac{5}{3} \right)$C$\left( \frac{1}{3},1 \right)$D$\left( \frac{1}{3},2 \right)$

Show answer and solution▾

=$\left( \frac{1 + 3 - 3}{3},\frac{2 + 0 + 4}{3} \right) = \left( \frac{1}{3},2 \right)$

Source: Grass-G / M-28 Mathematics Paper FST 16 Jan.docx