Question bank/JEE Main/Physics
JEE MainPhysics
A positively charged particle is moved in a straight line to
the right from position x = -4 m to position x = -2 m by an external
agent. The electric potential at these positions in space are V(x =
-4m) = -4 volts and V(x = -2m) = -2 volts. Which statement is true
about the work done by the external agent moving the charge between
these positions and the electric field component parallel to the
direction of motion that the moving charged particle experiences? Assume
the particle is moved at constant speed.
Show answer and solution
wext = q (vs - vi) = q (-4 - (-2)) = -2q = -ve
E goes from higher potential to lower potential.
E goes from higher potential to lower potential.
Source: Grass-G / P-01 Physics Paper-01_Update.docx
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