Question bank/JEE Main/Physics

JEE MainPhysics

A positively charged particle is moved in a straight line to
the right from position x = -4 m to position x = -2 m by an external

agent. The electric potential at these positions in space are V(x =

-4m) = -4 volts and V(x = -2m) = -2 volts. Which statement is true

about the work done by the external agent moving the charge between

these positions and the electric field component parallel to the

direction of motion that the moving charged particle experiences? Assume

the particle is moved at constant speed.

Show answer and solution
wext = q (vs - vi) = q (-4 - (-2)) = -2q = -ve
E goes from higher potential to lower potential.

Source: Grass-G / P-01 Physics Paper-01_Update.docx

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