Question bank/JEE Main/Physics
JEE MainPhysics
In a Young's double slit experiment sources of equal
intensities are used. Distance between slits is d and wavelength of
light used is λ(λ << d). Angular separation of the nearest points on
either side of central maximum where intensities becomes half of the
maximum value is
Show answer and solution
[IMAGE] I + I + 2 [IMAGE] cos φ
2I = 2I + 2I cos φ
cos φ = 0
φ = [IMAGE] ∆x = [IMAGE] x = [IMAGE] θ =[IMAGE]








2I = 2I + 2I cos φ
cos φ = 0
φ = [IMAGE] ∆x = [IMAGE] x = [IMAGE] θ =[IMAGE]








Source: Grass-G / P-01 Physics Paper-01_Update.docx
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