Question bank/JEE Main/Physics

An electron starting from rest and accelerated through V =
20,000 V in an x-ray tube loses half the energy it acquired as it
approaches an atom of the target material. The remaining KE is lost in
subsequent interactions with other target atoms. Find the wavelength of
the radiation emitted in the first interaction.

A6.63B4.14C1.24D12.4

Show answer and solution▾

∆E = 1 × 104 eV = [IMAGE] λ = [IMAGE] nm = 0.124 nm

Source: Grass-G / P-01 Physics Paper-01_Update.docx