Question bank/JEE Main/Physics

The frequency of incident light falling on photo sensitive
substance is doubled. If E_1 is the kinetic energy of emitted electron
in first case and E_2 is the kinetic energy in second case, then

AE_1 = E_2BE_2 = 2E_1CE_2 < 2E_1DE_2 > E_1

Show answer and solution▾

. [IMAGE] Dividing both equations,
[IMAGE] Hence, E_2 > 2E_1

Source: Grass-G / P-02 Physics Paper-02_Update.docx