Question bank/JEE Main/Physics

A conducting loop of area 10 cm^2 and resistance 1 W is kept
in a time varying magnetic field, perpendicular to its plane, which is
zero at t = 0. The current I induced in the loop as a function of time t
is given as I = (8t + 1) mA. The magnetic field B as a function of time
t is

A(4t^2 + t + 1) TB(4t^2 + t + 2) TC(4t^2) TD(4t^2 +
t) T

Show answer and solution▾

[IMAGE] = (8t + 1) ´ 10^-3 A
⇒ ε = R(8t + 1) × 10^-3
[IMAGE] = R (8t + 1) × 10^-3 and [IMAGE] ∴ [IMAGE] (8t + 1) ´ 10^-3 ⇒ [IMAGE] ⇒ [IMAGE] ⇒ [IMAGE] ⇒ [IMAGE] ⇒ [IMAGE]

Source: Grass-G / P-02 Physics Paper-02_Update.docx