Question bank/JEE Main/Physics
JEE MainPhysics
Two tuning forks are producing 6 beats/s. The frequency of
first tuning fork is 256 Hz. Now, first tuning fork is loaded with wax.
As a result the beat frequency becomes 4 beats/s. Now some portion of
the wax is removed from first tuning fork. As a result the beat
frequency becomes 0 beats/s. Then the frequency of first tuning fork
after waxing (the condition when beat frequency is 4 beats/s) will be
Show answer and solution
Since beat frequency is 6 Hz, therefore, frequency of second
fork will be either 262 Hz or 250 Hz. Since on loading with wax beat
frequency decreases, frequency of second fork should be 250 Hz. So after
waxing, the frequency of first tuning fork should be either 252 or 246
Hz. Since after removing a portion of wax from first fork beat frequency
becomes zero. Therefore frequency of first fork after waxing should be
246 Hz.
fork will be either 262 Hz or 250 Hz. Since on loading with wax beat
frequency decreases, frequency of second fork should be 250 Hz. So after
waxing, the frequency of first tuning fork should be either 252 or 246
Hz. Since after removing a portion of wax from first fork beat frequency
becomes zero. Therefore frequency of first fork after waxing should be
246 Hz.
Source: Grass-G / P-02 Physics Paper-02_Update.docx
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