Question bank/JEE Main/Physics
JEE MainPhysicsTough
Block M slide down on frictionless inclined plane as shown. Find
frictional force acting on block m while it is at rest with respect to
the block M. (m = 2kg, M = 5kg, g = 10 m/sec2)
Show answer and solution
a = g sin 37°
f = m × a × cos 37°
TOPIC: NLM
SUB TOPIC: NEWTON'S SECOND LAW
f = m × a × cos 37°
TOPIC: NLM
SUB TOPIC: NEWTON'S SECOND LAW
Source: Grass-G / P-03 Paper 1 (Physics) Eng. + Hindi 24-8-2020.docx
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