Question bank/JEE Main/Physics

The potential energy for a force field is given by U (x, y) = sin
(x + y), the magnitude of force acting on the particle at (0, π/4) is

A1B0
U (x, y) = sin (x + y)
(0, π/4)

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[IMAGE] = - cos (x + y) [IMAGE] -
cos (x + y) [IMAGE] TOPIC: WPE
SUB TOPIC: POTENTIAL ENERGY

Source: Grass-G / P-03 Paper 1 (Physics) Eng. + Hindi 24-8-2020.docx