Question bank/JEE Main/Physics

A particle is projected upwards with velocity v = 30 m/s. There are
two points A and B at heights hA = 25 m and hB = 40m. If the particle
crosses point B twice in a time interval ∆t. Then, it will also cross A
twice in a time interval equal to

A2∆tB1.5 ∆tC3∆tD2.5 ∆t
v = 30 m/s. hA = 25 hB = 40
A B B ∆t
A

Show answer and solution▾

hmax = [IMAGE] = 45m
Time to go from C to B,
5 = [IMAGE] gt2
t = 1s, So ∆t = 2s
Time to go from C to A,
20 =[IMAGE] gt2
t = 2s
∆tA = 2 × 2 = 4s = 2∆t
TOPIC: KINEMATIC
SUB TOPIC: MOTION UNDER GRAVITY

Source: Grass-G / P-03 Paper 1 (Physics) Eng. + Hindi 24-8-2020.docx