Question bank/JEE Main/Physics
JEE MainPhysicsModerate
40 m
80 m
Show answer and solution
With standard kinematics, we get
[IMAGE] y = [IMAGE] gt2, t = [IMAGE] = 2.86 s
x = vxt, vx =[IMAGE] = 28.0 m/s
vy2 - v02 = 2a(y - y0)
vy = -[IMAGE] = -[IMAGE] = 28.0 m/s
θ = A tan[IMAGE] = 315°
TOPIC:KINEMATIC
SUB TOPIC: 2 D
[IMAGE] y = [IMAGE] gt2, t = [IMAGE] = 2.86 s
x = vxt, vx =[IMAGE] = 28.0 m/s
vy2 - v02 = 2a(y - y0)
vy = -[IMAGE] = -[IMAGE] = 28.0 m/s
θ = A tan[IMAGE] = 315°
TOPIC:KINEMATIC
SUB TOPIC: 2 D
Source: Grass-G / P-03 Paper 1 (Physics) Eng. + Hindi 24-8-2020.docx
Need a video for this idea?
Scan any doubt from your notes and get a whiteboard explanation.