Question bank/JEE Main/Physics

The position of a projectile launched from the origin at t = 0 is
given by [IMAGE] at
t = 2s. If the projectile was launched at an angle θ from the
horizontal, then θ is (take g=10 ms-2)

A[IMAGE] t = 0 t = 2s
 θ  θ  (g = 10 ms-2 )

Show answer and solution▾

[IMAGE] 40 = Sx = V cos θ × t
50 = Sy = V sin θt - [IMAGE] gt2
t = 2 given
θ = tan-1 [IMAGE] TOPIC: KINEMATIC
SUB TOPIC: 2 D

Source: Grass-G / P-03 Paper 1 (Physics) Eng. + Hindi 24-8-2020.docx