Question bank/JEE Main/Physics
JEE MainPhysicsModerate
The acceleration of the blocks (A) and (B) respectively in
situation shown in the figure is: (pulleys & strings are massless)
Show answer and solution
aA = 2aB...(1)
mAg - T = mAaA...(2)
2T - mBg = mBaB...(3)
Solving, we get aA =[IMAGE] & aB
TOPIC: NLM
SUB TOPIC: NEWTON'S SECOND LAW
mAg - T = mAaA...(2)
2T - mBg = mBaB...(3)
Solving, we get aA =[IMAGE] & aB
TOPIC: NLM
SUB TOPIC: NEWTON'S SECOND LAW
Source: Grass-G / P-04 Paper 2 (Physics) Eng.+ Hindi 24-8-2020.docx
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