Question bank/JEE Main/Physics
JEE MainPhysicsModerate
The displacement x of a body of mass 1 kg on horizontal smooth
surface as function of time t is given by x =[IMAGE].
The work done in the first one second is

Show answer and solution
dW = F.dx
x =[IMAGE] v =[IMAGE] = t3 ⇒ dx = t3dt
[IMAGE] = 3t2
[IMAGE] t3 dt
TOPIC: WPE
SUB TOPIC: WORK DONE BY VARIABLE FORCE




x =[IMAGE] v =[IMAGE] = t3 ⇒ dx = t3dt
[IMAGE] = 3t2
[IMAGE] t3 dt
TOPIC: WPE
SUB TOPIC: WORK DONE BY VARIABLE FORCE




Source: Grass-G / P-04 Paper 2 (Physics) Eng.+ Hindi 24-8-2020.docx
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