Question bank/JEE Main/Physics
JEE MainPhysicsTough
A block of weight 10 N produces an extension of 9 cm when it is
hung by an elastic spring of length 60 cm and is in equilibrium. The
spring is cut into two parts, one of length 40 cm and the other of
length 20 cm. Another weight of 20 N hangs in equilibrium supported by
both parts as shown in the figure. Find the total extension of the two
parts of the spring (in cm) now.
10N 60 cm 9cm, 40
cm 20 cm 20N
(cm )
Show answer and solution
10 = k ×[IMAGE] k =[IMAGE] k1 × 4 = k × 60 =[IMAGE] × 60
k1 =[IMAGE] k2 × 20 = k × 60 ⇒ k2 =[IMAGE] kq = k1 + k2 = 500
10 = 500 x ⇒ x =[IMAGE] m = 2 cm
TOPIC: NLM
SUB TOPIC: SPRING
k1 =[IMAGE] k2 × 20 = k × 60 ⇒ k2 =[IMAGE] kq = k1 + k2 = 500
10 = 500 x ⇒ x =[IMAGE] m = 2 cm
TOPIC: NLM
SUB TOPIC: SPRING
Source: Grass-G / P-04 Paper 2 (Physics) Eng.+ Hindi 24-8-2020.docx
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