Question bank/JEE Main/Physics
JEE MainPhysicsModerate
A point moves according to the law, x = at and y = at (1- αt),
where a and α are positive constants and t is time. Find the moment at
which angle between velocity vector and acceleration vector
Show answer and solution
x = at ⇒ vx = a ⇒ ax = 0
y = at - aαt2 ⇒ vy =[IMAGE] = a - 2αat
ay =[IMAGE] = - 2αa
[IMAGE] = av cos θ
= (2αa) [IMAGE] Solve to get, [IMAGE] TOPIC:KINEMATIC
SUB TOPIC: ACCERATION
y = at - aαt2 ⇒ vy =[IMAGE] = a - 2αat
ay =[IMAGE] = - 2αa
[IMAGE] = av cos θ
= (2αa) [IMAGE] Solve to get, [IMAGE] TOPIC:KINEMATIC
SUB TOPIC: ACCERATION
Source: Grass-G / P-04 Paper 2 (Physics) Eng.+ Hindi 24-8-2020.docx
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