Question bank/JEE Main/Physics
JEE MainPhysicsModerate
A particle is projected at an angle tan-1[IMAGE].
Find the height at which velocity of the particle is
[IMAGE] (m/sec). (g = 10 ms-2)


Show answer and solution
tan θ
[IMAGE] Uy [IMAGE] 9 = 27 + 2(-10)Sy
Sy = 0.9






[IMAGE] Uy [IMAGE] 9 = 27 + 2(-10)Sy
Sy = 0.9






Source: Grass-G / P-04 Paper 2 (Physics) Eng.+ Hindi 24-8-2020.docx
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