Position of a particle moving on x-axis as a function of time t is given by meter. What is the velocity of the particle when its acceleration is zero?

JEE MainPhysicsModerateMotion in 1D

Position of a particle moving on x-axis as a function of time t
is given by
$x = \left( t^{3} - 6t^{2} + 3t + 4 \right)$ meter.
What is the velocity of the particle when its acceleration is zero?

Show answer and solution

v = 3t^{2} - 12t + 3

a = 6t - 12 = 0

\Rightarrow t = 2\sec

v(t = 2sec) = - 9m/s

Source: Grass-G / P-05 Physics paper 10 October.docx

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