Question bank/JEE Main/Physics

JEE MainPhysicsModerateMotion in 1D

The velocity of an object moving rectilinearly is given as a
function of time by
v=4t−3t2v = 4t - 3t^{2}, where v is in m/s and t is in
seconds. The average velocity of particle between t=0 to t=2 seconds is

Show answer and solution
<v>=∫02\mspace2muvdt∫02\mspace2mudt=∫02\mspace2mu(4t−3t2)dt2=0< v > = \frac{\int_{0}^{2}\mspace{2mu} vdt}{\int_{0}^{2}\mspace{2mu} dt} = \frac{\int_{0}^{2}\mspace{2mu}\left( 4t - 3t^{2} \right)dt}{2} = 0

Source: Grass-G / P-05 Physics paper 10 October.docx

Need a video for this idea?

Scan any doubt from your notes and get a whiteboard explanation.