JEE MainPhysicsEasyError analysis

A physical quantity A is related to fourobservation a, b, c and
d as follows $A = \frac{a^{2}b^{3}}{c\sqrt{d}}$
The percentage errors of measurement in a, b, c and d are 1, 3, 2 and 2 respectively. Whatis the percentage error in the quantity A ?

Show answer and solution

\frac{dA}{A} = 2\frac{da}{a} + 3\frac{db}{b} + \frac{dc}{c} + \frac{1}{2}\frac{dd}{d}

\%\frac{dA}{A} = 2*1 + 3*3 + 1*2 + \frac{1}{2}*2 = 14\%.

Source: Grass-G / P-05 Physics paper 10 October.docx

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