Question bank/JEE Main/Physics

JEE MainPhysicsModerateUnit and dimension

Dimensions of gravitational constant are

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G=Fr2m1m2; [G]=[Fr2m1m2]=[MLT−2L2M2]=[M−1L3T−2]G = \frac{Fr^{2}}{m_{1}m_{2}};\ \lbrack G\rbrack = \left\lbrack \frac{Fr^{2}}{m_{1}m_{2}} \right\rbrack = \left\lbrack \frac{MLT^{- 2}L^{2}}{M^{2}} \right\rbrack = \left\lbrack M^{- 1}L^{3}T^{- 2} \right\rbrack

Source: Grass-G / P-05 Physics paper 10 October.docx

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