JEE MainPhysicsToughProjectile Motion

Two seconds after projection, a projectile is travelling in a
direction inclined at 30º to the horizontal after one more second, it is
travelling horizontally. Then the speed of projection(u) and angle of
projection ( $\theta$ ) are given by

Show answer and solution

T = 6sec = \frac{2usin\theta}{g} \Rightarrow usin\theta = 30

\tan 30^{\circ} = \frac{{usin}\theta - gt}{{ucos}\theta} = \frac{30 - 20}{{ucos}\theta}

which
gives

ucos\theta = 10\sqrt{3}

$$tan\theta =

Source: Grass-G / P-05 Physics paper 10 October.docx

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