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JEE MainPhysicsModerateError analysis

A wire has a mass 0.3 ± 0.0030.3\ \pm \ 0.003 g, radius
0.5 0±0.0050.5\ 0 \pm 0.005cm and length 6±0.066 \pm 0.06cm. What is the maximum
percentage error in the measurement of density?

Show answer and solution
dρA=dmm+2drr+dll\frac{d\rho}{A} = \frac{dm}{m} + 2\frac{dr}{r} + \frac{dl}{l}
%dρA=(0.0030.3+2∗0.0050.5+0.066)∗100=4%\%\frac{d\rho}{A} = \left( \frac{0.003}{0.3} + 2*\frac{0.005}{0.5} + \frac{0.06}{6} \right)*100 = 4\%

Source: Grass-G / P-05 Physics paper 10 October.docx

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