Question bank/JEE Main/Physics

JEE MainPhysicsModerateMotion in 1D

A particle moves along x-axis with initial position x=0. Its
velocity varies with x-coordinate as shown in graph. The acceleration

'a" of this particle varies with x as

Show answer and solution
The linear relationship between V and x is V=−mx+CV = - mx + C
where m and C are positive constants.

Acceleration

a=vdVdx=−m(−mx+C)a = v\frac{dV}{dx} = - m( - mx + C)
Hence the graph relating a tox is.

Source: Grass-G / P-05 Physics paper 10 October.docx

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