A particle is projected up an inclined plane of inclination at an elevation to the horizontal. If the particle strikes the inclined plane at right angles then

JEE MainPhysicsToughProjectile Motion

A particle is projected up an inclined plane of inclination
$\beta$ at an elevation $\alpha$ to the horizontal. If the particle
strikes the inclined plane at right angles then $\tan\alpha =$

Show answer and solution

T = \frac{2usin(\alpha - \beta)}{gcos\beta}

......(1)

O = ucos(\alpha - \beta) - (gsin\beta)T

\Rightarrow T = \frac{ucos(\alpha - \beta)}{gsin\beta}

......(2)
from (1) &(2)

2tan(\alpha - \beta) = cot\beta

\Rightarrow tan\alpha = (cot\beta + 2tan\beta)

Source: Grass-G / P-05 Physics paper 10 October.docx

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