Question bank/JEE Main/Physics

A man who can swim at the rate of $2km/hr$ (in still river)
crosses a river to a point exactly opposite on the other bank by
swimming at an angle of 60º perpendicular direction of river flow of the
water in the river. The velocity of the water current in $km/hr$ is

A1B2C$1/2$D$\sqrt{3}$

Show answer and solution▾

Let speed of current be u. For net velocity ofman to be normal
to river flow.
$2sin60^{\circ} = u$
or$u = \sqrt{3}km/hr$

Source: Grass-G / P-05 Physics paper 10 October.docx