Question bank/JEE Main/Physics

Initially the block is at rest acceleration of the block is

A$2\ m/s^{2}$B$0\ m/s^{2}$C$1\ m/s^{2}$D$0.5\ m/s^{2}$

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[IMAGE] $N + 24 - 100 = 0$ For vertical direction
$\therefore N = 76N$
Now, $0 \leq f_{s} \leq \mu_{s}N\$
$0 \leq f_{s} \leq 76 \times 0.5$
$0 \leq f_{s} \leq 38N$
$\therefore 32 < 38\text{ Hence }f = 32$
$\therefore\ \$Acceleration of block is zero.

Source: Grass-G / P-06 Physics paper 14 October.docx