Question bank/JEE Main/Physics

JEE MainPhysicsModerateNewton's Laws of Motion

A uniform sphere of weight w and radius 3 m is being held by a
string of length 2 m. attached to a frictionless wall as shown in the

figure. The tension in the string is
5wn\frac{5w}{n} then find the value
of n.

Show answer and solution
[IMAGE] From geometry:
cos⁡θ=35\cos\theta = \frac{3}{5}
sin⁡θ=45\sin\theta = \frac{4}{5}
As sphere is at equilibrium

Tsin⁡θ=wT\sin\theta = w
T(45)=wT\left( \frac{4}{5} \right) = w
T=5w4T = \frac{5w}{4}

Source: Grass-G / P-06 Physics paper 14 October.docx

Need a video for this idea?

Scan any doubt from your notes and get a whiteboard explanation.