Question bank/JEE Main/Physics

Two forces of 6 N and 3 N are acting on the two blocks of 2 kg
and 1 kg kept on frictionless floor. The force exerted on 2 kg block by
1 kg block is 2 n then find the value of n.

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[IMAGE] Both blocks are constrained to move with same acceleration.
$6 - N = 2a\ \ \ \ \ \ \$[Newtons II law for 2kg block]
$N - 3 = 1a$ [Newton's II law for 1 kg block]
This gives a= 1m/s^2
Therefore, N =4 N

Source: Grass-G / P-06 Physics paper 14 October.docx