Question bank/JEE Main/Physics

JEE MainPhysicsModerateNewton's Laws of Motion

System shown in figure is in equilibrium. The magnitude of change
in tension in the string just before and just after, when one of the

spring is cut. Mass of both the blocks is same and equal to m and

springconstant of both springs is k. (Neglect any effect of rotation)

Show answer and solution
Before cutting the spring
After cutting the spring

[IMAGE] 2mg - mg = 2 ma

a = g/2

T3=mg/2T_{3} = mg/2
T2−T3=mg−mg/2=mg/2T_{2} - T_{3} = mg - mg/2 = mg/2

Source: Grass-G / P-06 Physics paper 14 October.docx

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