Question bank/JEE Main/Physics

JEE MainPhysicsModerateNewton's Laws of Motion

Two blocks of masses M1M_{1} and M2M_{2}are connected to each
other through a light spring as shown in figure. If we push mass
M1M_{1}
with force F and cause acceleration
a1a_{1} in mass M1M_{1}, what will
be the magnitude of acceleration in
M2M_{2}?

Show answer and solution
kx=M2a2kx = M_{2}a_{2} [Newton's II law for M2M_{2}]
By adding both equations.

F=M1a1+M2a2⇒a2=F−M1a1M2F = M_{1}a_{1} + M_{2}a_{2} \Rightarrow a_{2} = \frac{F - M_{1}a_{1}}{M_{2}}

Source: Grass-G / P-06 Physics paper 14 October.docx

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