Question bank/JEE Main/Physics

JEE MainPhysicsModerateNewton's Laws of Motion

In which of the following cases the magnitude of acceleration of
the block A will be maximum (Neglect friction and mass of pulley and
string)

Show answer and solution
(i) a=2mg−mg3m=g3a = \frac{2mg - mg}{3m} = \frac{g}{3} (ii)
a=2mg−mgm=ga = \frac{2mg - mg}{m} = g
(iii) a=2mgm=2ga = \frac{2mg}{m} = 2g (iv) a=2g3a = \frac{2g}{3}

Source: Grass-G / P-06 Physics paper 14 October.docx

More JEE Main questionsChapter practice

Need a video for this idea?

Scan any doubt from your notes and get a whiteboard explanation.

Scan a doubtView plans