Question bank/JEE Main/Physics

Two blocks of mass 10 kg and 4 kg are connected by a spring of
negligible mass and are placed on a frictionless horizontal surface. An
impulse gives a speed of $14{ms}^{- 1}$ to the heavier block in the
direction of the lighter block. Then, the velocity of the centre of mass
is

A$30\ {ms}^{- 1}$B$20\ {ms}^{- 1}$C$10\ {ms}^{- 1}$D$5\ {ms}^{- 1}$

Show answer and solution▾

$= \frac{10 \times 14 + 4 \times 0}{10 + 4} = 10m/s$.

Source: Grass-G / P-07 Physics paper 17 October.docx