Question bank/JEE Main/Physics

A particle moving on a circular path travels first one third
part of circumference in 2 sec & nextone third part in 1 sec. Average
angular velocity of the particle is $\frac{n\pi}{9}$ (in rad/sec). Then
valueof n.

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$\omega_{avg} = < \omega > = \frac{\ total\ \theta}{\ total\ \ time\ }$

Source: Grass-G / P-07 Physics paper 17 October.docx