Question bank/JEE Main/Physics

JEE MainPhysicsEasyRigid Body Dynamics

A constant torque acting on a uniform circular wheel changes its
angular momentum from 10 J-sec to60 J-sec in 4 sec. The torque in Nm is
2.5n. Find the value of n.

Show answer and solution
τ=dLdt=60−104=12.5\tau = \frac{dL}{dt} = \frac{60 - 10}{4} = 12.5 Nm

Source: Grass-G / P-07 Physics paper 17 October.docx

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