JEE MainPhysicsModerateThermodynamics

A monoatomic ideal gas follows the process:
TV^3/2 = constant
The molar specific heat for this process is: (R = gas constant).

Show answer and solution

TV^3/2 = constant

\frac{(P \vee )V^{3/2}}{nR} =

constant

{PV}^{\frac{5}{2}} =

constant

{PV}^{x} =

constant

x = \frac{5}{2}

C = C_{v} + \frac{R}{1 - x}

For polytropic process,

C = \frac{3}{2}R + \frac{R}{1 - \frac{5}{2}} = \frac{5R}{6}

Source: Grass-G / P-08 Physics paper 23 October.docx

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