Question bank/JEE Main/Physics

JEE MainPhysicsModerateThermodynamics

V - T diagram for a process of a given mass of ideal gas is as
shown in the figure. During the process pressure of gas.

Show answer and solution
V=KT+CV = KT + C
P=nRTVP = \frac{nRT}{V}
⇒P=nRTKT+C\Rightarrow P = \frac{nRT}{KT + C}
dPdT=nRC(KT+C)2\frac{dP}{dT} = \frac{nRC}{(KT + C)^{2}}
As C < 0 by diagram
⇒dPdT<0\Rightarrow \frac{dP}{dT} < 0 for all T
⇒\Rightarrow P continuously decreases

Source: Grass-G / P-08 Physics paper 23 October.docx

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