Question bank/JEE Main/Physics

JEE MainPhysicsModerateThermodynamics

For an adiabatic process graph between PV&V for a sample of
ideal gas will be

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PV α TPV\ \alpha\ T
 for adiabatic process, 

TVγ−1= {TV}^{\gamma - 1} = \ constant

Source: Grass-G / P-08 Physics paper 23 October.docx

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