Question bank/JEE Main/Physics

JEE MainPhysicsModerateThermodynamics

The expansion of unit mass of an ideal gas atconstant pressure
is show in the diagram. Here

Show answer and solution
PV=nRT(K)PV = nRT(K)
V=nRPT(K)V = \frac{nR}{P}T(K)
V=nRP[Tco+273]V = \frac{nR}{P}\lbrack T_{c}^{o} + 273\rbrack
V=nRPTco+273nRPV = \frac{nR}{P}T_{c}^{o} + 273\frac{nR}{P}
⇒Tco=PnRV−273\Rightarrow T_{c}^{o} = \frac{P}{nR}V - 273
y=mx−cy = mx - c

Source: Grass-G / P-08 Physics paper 23 October.docx

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