Question bank/JEE Main/Physics

JEE MainPhysicsModerateOscillation

A simple pendulum of length 50cm and bob's mass 100g is
oscillating in the air. A damping force f = 0.0693V acts due to air,

where V is speed of bob. At any time it has a amplitude A. How much time

it will take so that amplitude becomes half of initial value.

Show answer and solution
A=A0e−bt2mA = A_{0^{e}}\frac{- bt}{2m}
A02=A0e−bt2m⇒bt2m=ln⁡2\frac{\text{A}_{0}}{2} = \text{A}_{0^{\text{e}}}\frac{- \text{bt}}{2\text{m}} \Rightarrow \frac{\text{bt}}{2\text{m}} = \ln 2

Source: Grass-G / P-09 Physics paper 26 October.docx

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