Question bank/JEE Main/Physics

A particle is executing SHM between points
-[IMAGE] and [IMAGE], as shown in
figure-I. The velocity V(t) of the particle is partially graphed and
shown in figure-II. Two points A and B corresponding to time
are marked on the V(t) curve

AAt time [IMAGE], it is going towardsBAt time [IMAGE], its speed is increasing.CAt time [IMAGE], its position lies in between
[IMAGE] and ODThe phase difference ∆φ between points A and B must be expressed
as 90°
<∆φ< 180°.

Show answer and solution▾

At time [IMAGE], velocity of the particle is
negative i.e. going towar. From the graph, at
time [IMAGE], its speed is decreasing. Therefore
particle lies in between [IMAGE] and

Source: Grass-G / P-09 Physics paper 26 October.docx